Write the number of zeroes of the polynomial y = f(x) whose graph is given below
We find that, y = f(x) cuts the x-axis at 3 points therefore, the number of zeroes of f(x) is 3.
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Write the zeroes of the polynomial x2+2x+1.
Let, f(x) = x2 + 2x + 1 for the zero of the polynomial f(x) 0 ⇒ x2 + x + x + 1 = 0 ⇒ x(x + 1) + 1 (x + 1) = 0 ⇒ (x+ 1)(x+ 1) = 0 ⇒ x = –1 Hence –1 is the zero of the given polynomial